Chemical Kinetic Formulas

Chemical Kinetics is an Important Topic in Physical Chemistry and helps you understand different types of Chemical Reactions. In this article of ours, you will learn about Chemical Kinetic Formulas to make you familiar with the concept better. Quickly revise the Chemical Kinetics Formulae over here and start applying them while solving related problems.

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Formula Sheet for Chemical Kinetics

Going through the Chemical Kinetics Cheat Sheet you will have an overview of what Chemical Kinetics is exactly. Take your preparation to the next level by employing the Chemical Kinetic Formulae over here and solve the reactions quickly. Try to memorize the Simple Formulas on Chemical Kinetics provided as they form a stronger base during your study.

1. Rate of Reaction in the form of a Chemical reaction:
m1A + m2B + ……… → n1P + n2Q + n3R + ……..
Rate of reaction = \(-\frac{1}{m_{1}} \frac{d[A]}{d t}=-\frac{1}{m_{2}} \frac{d[B]}{d t}=\frac{1}{n_{1}} \frac{d[P]}{d t}=\frac{1}{n_{2}} \frac{d[Q]}{d t}\)

2. Unit of Rate constant:
K = mol1-Δn litΔn-1 sec-1

3. First order reaction:
K = \(\frac{2.303}{t} \log _{10} \frac{a}{(a-x)}\)
& t1/2 = \(\frac{0.693}{\mathrm{K}}\)
& [A]t = [A]0e-kt (wilhelmy equation)
K = \(\frac{2.303}{t} \log \left(\frac{\mathbf{v}_{\infty}-\mathbf{v}_{0}}{\mathbf{v}_{\infty}-\mathbf{v}_{t}}\right) h\)
& K = \(\frac{2.303}{t} \log _{10}\left(\frac{P_{0}}{P_{0}-x}\right)\)
& K = \(\frac{2.303}{t} \log \left(\frac{r_{\infty}-r_{0}}{r_{\infty}-r_{t}}\right)\)
n = 1 + \(\frac{\log _{10}\left(t_{1 / 2}\right)_{1}-\log _{10}\left(t_{1 / 2}\right)_{2}}{\log _{10}\left(a_{2}\right)-\log _{10}\left(a_{1}\right)}\)
Chemical Kinetic formulas img 1
Chemical Kinetic formulas img 2

4. Second Order Reaction:
Case: (i) When concentration of A and B taking same.
K2 = \(\frac{1}{t}\left(\frac{x}{a(a-x)}\right)\)

(ii) When concentration of A and B are taking different –
K2 = \(\frac{2.303}{t(a-b)} \log \frac{b(a-x)}{a(b-x)}\)
t1/2 = \(\frac{1}{\mathrm{K}_{2} \mathrm{a}}\)
& Chemical Kinetic formulas img 3

5. Zero Order Reaction:
x = Kt & t1/2 = \(\frac{\mathrm{a}}{2 \mathrm{K}}\)
The rate of reaction is independent of the concentration of the reacting substance.

6. Third Order Reaction:
K = \(\frac{1}{t} \cdot \frac{x(2 a-x)}{2 a^{2}(a-x)^{2}}\) & t1/2 = \(\frac{3}{2 a^{2}}\)

7. Difference between Molecularity and Order of Reaction:

Molecularity Order of Reaction
1. It is the number of molecules of reactants concentration terms taking part in elementary step of a reaction. 1. It is sum of power raised on the rate expression.
2. Molecularity is a theoretical value and is derived from mechanism. 2. Order of a reaction is experiment value derived from rate expression.
3. Molecularity can neither be zero nor fractional. 3. Order of a reaction can be zero, fractional for integer.
4. It is a assigned for each step of mechanism separately. 4. Order of a reaction may have negative value.
5. It is a assigned for each step of mechanism separately. 5. It is as singed for overall reaction.
6. It is independent of pressure and temperature. 6. It depends upon pressure and temperature.

8. Difference between Rate of Reaction & Rate constant:

Rate of reaction Reaction rate constant
1. Rate of reaction is called as the change in concentration reactant or product per unit time. 1. Rate constant is the proportionality constant in the rate Saw equation. When molar concentration of reactants is taken as unity, its value is equal to rate of reaction.
2. Rate of reaction varies with concentration of the reactant. 2. Since it is proportionality constant for a articular reaction, it is independent of the concentration of the reactant.
3. Rate of reaction increases with increase in temperature. 3. Rate constant value also varies directly with the temperature.
4. The units of rate of reaction is mole litre-1 time-1. 4. The units of reaction rate constant depends upon the order of reaction i.e. its unit differs according to order of reaction.

9. Difference between Rate Law and Law of Mass Action:

Rate Law Law of Mass action
1. It is an experimentally observed law. 1. It is a theoretical law.
2. It depends on the concentration terms on which the rate of reaction actually depends
eg. for the reaction.
aA + bB → Products
Rate law, Rate = k[A]m[B]n
2. It is based upon the stoichiometry of the equation
eg., for the reaction,
aA + bB → Product
Rate = k [A]a[B]b

10. Determination of order:
\(\frac{t_{2}}{t_{1}}=\left[\frac{a_{1}}{a_{2}}\right]^{n-1}\) [∵ t1/2 ∝ \(\frac{1}{a^{n-1}}\)]
t(half life) ………….. a (Initial conc.)

11. Arrhenius equation:
k = Ae-Ea/RT
& slope = \(\frac{-\mathrm{E}_{\mathrm{a}}}{2.303 \mathrm{R}}\)
Temperature Coefficient = \(\frac{K a t\left(t+10^{\circ} C\right)}{K a t t^{\circ} C}=\frac{K_{35^{\prime} C}}{K_{25^{\prime} C}}\)

12. Positive catalyst increases the rate of reaction while, the negative catalyst decreases.

Process Catalyst
1. Haber’s process for synthesis of ammonia Iron Mo (promoter)
2. Contact process for manufacture of H2SO4 Pt, V2O5
3. Ostwald process for manufacture of HNO3 Pt gauze
4. Deacon’s process for manufacture of Cl2 Cu2Cl2
5. Bosch process for manufacture of H2 Fe2O3 + Cr2O3
6. Manufacture of vegetable ghee Ni
7. Manufacture of C2H5OH from sucrose Invertase, Zymase
8. Manufacture of C2H5OH from starch Diastase, Maltase
9. Methanol from H2 and CO ZnO & Cr2O3
10. Dehydrogenation of alkenes H3PO4 on kieselguhr
11. Acetic acid by oxidation with air V2O5

13. log\(\left(\frac{\mathrm{k}_{2}}{\mathrm{k}_{1}}\right)\) = \(\frac{\mathrm{E}_{\mathrm{a}}}{2.303}\left(\frac{\mathrm{T}_{2}-\mathrm{T}_{1}}{\mathrm{T}_{1} \mathrm{T}_{2}}\right)\)

14. Energy of activation = Threshold energy – Energy of reactant
ΔE = Ep – ER
Einstein
Chemical Kinetic formulas img 4

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