Mole Concept Formulas

The concept of Mole is quite important and you might be curious to know the Mole Concept Formulas. Don't worry to help you out we have jotted the Mole Concept Related Formulae complete list here. Have a quick look at the Mole Concept Formulae Sheet and start employing them while solving related problems. You will no longer feel the Concept of Mole difficult with our Mole Formulas & Tables prevailing.

Solve your chemistry problems fastly and efficiently taking the help of Chemistry Formulas and learn about the Concepts without much effort.

Mole Concept Cheat Sheet & Tables

Support your learning regarding the Mole Concept with the Cheat Sheet on the Concept of Mole. Use this resource as supplements during your preparation and get a good grip on the concept. The Mole Concept will no longer be tough to you with the below outlined Mole Concept Formulae Sheet.

1. Laws of Chemical Combination:
(i) Law of conservation of mass-[Lavoisier, 1744]:
Matter is neither created nor destroyed in the course of chemical reaction although it may change from one form to other

(ii) Law of definite proportion [Proust, 1799]:
The composition of a compound always remains a constant i.e. the ratio of weights of different elements in a compound; no matter by j whatever method, it is prepared or obtained from different sources, remains always a constant

(iii) Law of multiple proportion [John Dalton, 1804]:
According to this law, when two elements A and B combine to form more than one chemical compound then different weights of A, which combine with a fixed weight of B, are in a proportion of simple whole number

(iv) Law of reciprocal proportions [Ritche, 1792-94]:
When two elements combines separately with third element and form j different types of molecules, their combining ratio is directly i reciprocated if they combine directly

(v) The law of Gaseous volume: [Gay Lussac 1808]:
According to this law , when gas combine , they do so in volume which bear a simple ratio to each other and also to the product formed provided all gases are measured under similar conditions.

2. Limiting Reagent:
It may be defined as the reactant which is completely consumed during the reaction is called limiting reagent.
☞ Mole concept:
GAM = 1 gm atom
= 6.02 × 1023 atom.
GMM = 1 gm mole
= 6.02 × 1023 molecules
NA = 6.02 × 1023
☞ Mass of ‘x’ atoms of an element = \(\left[\frac{\mathrm{GAM}}{\mathrm{N}_{\mathrm{A}}}\right]\).x
☞ Mass of‘y’ molecules of a substance = \(\left[\frac{\mathrm{GMM}}{\mathrm{N}_{\mathrm{A}}}\right]\).y
☞ Number of atoms in w gm of element = \(\left[\frac{w}{G A M}\right]\) × NA
☞ Number of atoms in ‘n’ moles of substance = n × NA
☞ Number of molecules in w gm of substance = \(\left[\frac{w}{G M M}\right]\) × NA
☞ Number of molecules in ‘n’ moles of substance = n × NA
☞ Moles for y molecules = \(\frac{y}{N_{A}}\)
☞ Moles for y atoms (element) = \(\frac{y}{N_{A}}\)
☞ Moles (gases) at NTP = \(\frac{\text { volume }(\mathrm{L})}{22.4}\)

Explore various concepts of subjects like Maths, Physics, Chemistry altogether at chemistrycalc.com and learn the concepts thoroughly.