Find the Oxidation Numbers PbO_2

$P b O_{2}$

Step 1

Since $P b$ is in column $0$ of the periodic table, it will share $0$ electrons and use an oxidation state of $0$ .

$P b = 1 (0) = 0$

Step 2

Since $O$ is in column $6$ of the periodic table, it will share $6$ electrons and use an oxidation state of $6$ .

$O = 2 (- 2) = - 4$

Step 3

This is the full list of oxidation states for this molecule.

$P b = 0, O = - 4$