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2-chloropropanoic acid has a Ka of 1.48E-3. Write an expression for Ka and hence or otherwise, calculate the pH of a 0.35M solution of 2-chloropropanoic acid
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3-Methylpent-2-ene (CH3CH=C(CH3)CH2CH3) reacts with Hydrogen Chloride(HCl) forming a major and minor product. Please name the reaction, draw the mechanism for the formation of the major product and briefly explain why there is a major and a minor product.
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