Find the Density at STP CCl_4

$C \cdot C l_{4}$

Step 1

To find the mass of $1$ mole of $C C l_{4}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $C \cdot C l_{4}$ $=$ $(mass of C)$ + $4 (mass of Cl)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $C \cdot C l_{4}$ $=$ $(12.01000022)$ + $4 (35.45000076)$

Step 3

Simplify the result.

Multiply $4$ by $35.45000076$ .

mass of $1$ mole of $C C l_{4} = 12.01000022 + 141.80000305 g$

Add $12.01000022$ and $141.80000305$ .

mass of $1$ mole of $C C l_{4} = 153.81000328 g$

Step 4

One mole of any gas occupies $22.4 L$ at STP (standard temperature and pressure).

$V = 22.4 L$

Step 5

Density is mass over volume.

$\frac{153.81000328 g}{22.4 L}$

Step 6

Factor $153.81000328$ out of $153.81000328 g$ .

$\frac{153.81000328 (g)}{22.4 L}$

Step 7

Factor $22.4$ out of $22.4 L$ .

$\frac{153.81000328 (g)}{22.4 (L)}$

Step 8

Separate fractions.

$\frac{153.81000328}{22.4} \cdot \frac{g}{L}$

Step 9

Divide $153.81000328$ by $22.4$ .

$6.866518 \frac{g}{L}$

Step 10

Combine $6.866518$ and $\frac{g}{L}$ .

$\frac{6.866518 g}{L}$

Find the Density at STP CCl_4

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