Find the Density at STP ClAr

$C l A r$

Step 1

To find the mass of $1$ mole of $C l A r$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $C l A r$ $=$ $(mass of Cl)$ + $(mass of Ar)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $C l A r$ $=$ $(35.45000076)$ + $(39.95000076)$

Step 3

Simplify the result.

Remove parentheses.

mass of $1$ mole of $C l A r = 35.45000076 + 39.95000076 g$

Add $35.45000076$ and $39.95000076$ .

mass of $1$ mole of $C l A r = 75.40000152 g$

Step 4

One mole of any gas occupies $22.4 L$ at STP (standard temperature and pressure).

$V = 22.4 L$

Step 5

Density is mass over volume.

$\frac{75.40000152 g}{22.4 L}$

Step 6

Factor $75.40000152$ out of $75.40000152 g$ .

$\frac{75.40000152 (g)}{22.4 L}$

Step 7

Factor $22.4$ out of $22.4 L$ .

$\frac{75.40000152 (g)}{22.4 (L)}$

Step 8

Separate fractions.

$\frac{75.40000152}{22.4} \cdot \frac{g}{L}$

Step 9

Divide $75.40000152$ by $22.4$ .

$3.36607149 \frac{g}{L}$

Step 10

Combine $3.36607149$ and $\frac{g}{L}$ .

$\frac{3.36607149 g}{L}$

Find the Density at STP ClAr

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